(12,25x^2)-7x=0

Solution for (12,25x^2)-7x=0 equation:

(12.25x^2)-7x=0

We add all the numbers together, and all the variables

-7x+(12.25x^2)=0

We get rid of parentheses

12.25x^2-7x=0

a = 12.25; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·12.25·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*12.25}=\frac{0}{24.5}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*12.25}=\frac{14}{24.5}
=7/12.25
$